Top Posters
Since Sunday
y
2
m
2
m
2
u
2
m
2
B
2
M
2
e
2
k
2
N
2
y
2
m
2
Home Q & A Board Science-Related Homework Help Mathematics
New Topic  
irina irina
wrote...
Go to Answer
Posts: 919
Rep: 26 0
12 years ago
Please help Frowning Face I honestly never learned this in class and I have a test soon! The question is : Find the equation of the tangent line to the graph of x^2(multiply by)y^2=1 at the point (4, 1/2) and at the point (4,-1/2)
Thank you!
Read 591 times
2 Replies
Replies
Answer accepted by topic starter
nywoodsnywoods
wrote...
#1
12 years ago
Sign in or Sign up in seconds to unlock everything for free
1

Related Topics

wrote...
#2
12 years ago
I can tell you how to find the equation of the tangent line.

To find the equation of the tangent line, you will have to take the derivative of the original function.
(x^2)(y^2) = 1
solve for y and you get:
y = 1/x
Now you take the derivative by first reorganizing the equation
y = x^-1
y = -x^-2
y = -1/x^2

So the equation of the tangent line will be: y = -1 / x^2
So at (4,0.5) the slope is -1/16 and the slope at (4,-0.5) is the same.

so the equation will become:
 y-y1=m(x2-x1)

y-0.5 = (-1/16)(x-4) at point (4,1/2)
or
y+0.5 = (-1/16)(x-4) at point (4,-1/2)
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  759 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 385
  
 395
  
 319
Your Opinion
How often do you eat-out per week?
Votes: 81
Previous poll results: Which industry do you think artificial intelligence (AI) will impact the most?