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juldina1 juldina1
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11 years ago
If the half life of strontium is 3500years, how much of a 10kg sample remains after 300 years?

I'm having trouble setting up the problem and solving it. I think I found the rate, r= (ln1/2)/3500 but I dont know what to do next
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wrote...
#1
11 years ago
P(x)=10e^(ln(1/2)/3500)t
P(300)=10e^(ln(1/2)/3500)(300)=9.423 kg
wrote...
#2
11 years ago Edited: 7 years ago, bio_man
Use y = Ce^(kt)...

½ = e^(3500k)
k = ln(½)/3500

Hence...

y = 10(½)^(t/3500)
y = 10(½)^(1/350)
y = 9.98 kg

Good luck!
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