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Chery Chery
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Posts: 3587
7 years ago
A proton, starting from rest, accelerates through a potential difference of 1.0 kV and then moves into a magnetic field of 0.040 T at a right angle to the   field.  What is the radius of the proton's resulting orbit? (e = 1.60 × 10-19 C, mproton = 1.67 × 10-27 kg)
A) 0.080 m
B) 0.11 m
C) 0.14 m
D) 0.17 m
Textbook 
College Physics

College Physics


Edition: 1st
Authors:
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Answer verified by a subject expert
noreyaganoreyaga
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Posts: 649
7 years ago Edited: A year ago, bio_man
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Chery Author
wrote...
7 years ago
Looked all over the internet for this, thank you for answering correctly
wrote...
3 years ago
Looked everywhere for this, thank you!
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