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Chery Chery
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Posts: 3594
5 years ago
After an electron has been accelerated through a potential difference of 0.15 kV, what is its de Broglie wavelength? (e = 1.60 × 10-19 C, melectron = 9.11 × 10-31 kg, h = 6.626 × 10-34 J ∙ s)
A) 0.10 nm
B) 1.0 nm
C) 1.0 mm
D) 1.0 cm
Textbook 

College Physics


Edition: 1st
Authors:
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slicealemonslicealemon
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5 years ago
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