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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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rileyblok rileyblok
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7 years ago
I tried to solve this already. I used the equation En= -2.179x10^-18/(n^2) J but didn't end up with the right answer. I don't know if I may have somehow plugged my numbers in wrong or if there's another equation I'm supposed to use. Please help if you can :-)
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Valued Member
7 years ago
1/λ = R (1/n'² - 1/n²)

Therefore λ = 1/(R (1/n'² - 1/n²) ) = 1/(1.0974 * 10^7 m^-1 * (1/3² - 1/7²)) = 1/(1.0974 * 10^7 m^-1 * (0.3333 - 0.0204) = 1/ (1.0974 * 10^7 m^-1 * 0.3129) = 1/3.435*10^6 m = 2.9115 * 10^-7 m.

We can convert this to frequency using the relationship c = λν therefore ν = c/λ = 2.998 * 10^8/2.9115 * 10^-7 = 1.0297 * 10^15 /s.

Next calculate the energy using the relationship E = h ν = 6.6261 * 10^-34 J.s * 1.0297 * 10^15 /s = 6.8229 * 10^-19 J= 6.823 * 10^-19 J.
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