Top Posters
Since Sunday
5
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
New Topic  
smmunday smmunday
wrote...
Posts: 85
Rep: 1 0
11 years ago
Assuming that radiation with lambda = 15.0 cm is used, that all the energy is converted to heat, and that 4.184 J is needed to raise the temperature of 1.00 g of water by 1.00 C, how many photons are necessary to raise the temperature of a 300 mL cup of water from 20 C to 95 C?
Read 3548 times
4 Replies
Replies
Answer accepted by topic starter
nusrse2014nusrse2014
wrote...
Posts: 10
Rep: 1 0
11 years ago
Sign in or Sign up in seconds to unlock everything for free

Related Topics

wrote...
11 years ago
energy of radiation = (planck's constant * speed of light) / wavelength

planck's constant = 6.62 x 10^-34
speed of light = 3 x 10^8
wavelength = 15 cm = 0.15 m

energy of radiation = (6.62 x 10^-34 x 3 x 10^8) / 0.15 = 1.324 x 10^-24 joules per photon

that is the energy of one photon because photons behaves both particle like and wave like

energy to heat water = water's specific heat x mass x (final temperature - initial temperature)
energy to heat water = 4.184 x 300 x 75 = 94140 joules

94140 / (1.324 x 10^-24) = 7.11 x 10^28 photons
wrote...
3 years ago
thank you
wrote...
3 years ago
Thank you
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  1248 People Browsing
Related Images
  
 110
  
 473
  
 283
Your Opinion