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Dash8er Dash8er
wrote...
Posts: 28
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11 years ago
NH3 + N2O ? N2 + H2O

I have always had a difficult time balancing chemical equations so it would be very helpful if anybody has some useful tips.

Thank you!
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wrote...
11 years ago
Count the number of each element on the left

3 N's
3 H's
1 O

So you need the same numbers on the right
wrote...
11 years ago
2NH3 + 3N2O ? 4N2 +3H2O
wrote...
11 years ago
2NH3 + 3N20 Rightwards Arrow 4N2 + 3H20

Tips:
1) Balance single elements last
2) Keep polyatomic ions together when possible. (H20 Rightwards Arrow HOH)
3) Make odds even when necessary.
4) Move back and forth, trying to find common mulitiples.
5) Reduce if possible.
wrote...
11 years ago Edited: 11 years ago, bio_man
Look at the hydrogen first. It's in only one place on the left and on the right. Notice I used the least common multiple of 2 and 3, in that 2x3 = 6 and 3x2 = 6.

2NH3 + N2O Rightwards Arrow N2 + 3H2O

Balance the oxygen next:

2NH3 + 3N2O Rightwards Arrow N2 + 3H2O

Nitrogen:

2NH3 + 3N2O Rightwards Arrow 4N2 + 3H2O
wrote...
11 years ago
The number of N's on the left side must equal the number of N's on the right side. This is the same for H's and O's as well. So all you need to do is do the simple calculations, and you should come out to (2)NH3+(3)N2O Rightwards Arrow (4)N2+(3)H2O
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