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tonio613 tonio613
wrote...
Posts: 73
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11 years ago
Lets look at the equation:
y^2+ x^2= r^2

Using chain rule and all that jazz, I get this as a derivative:
y'= -x(r^2-x^2)^(-1/2)
But finding the implicit derivative, I get a different answer:
y'= -x/y

What is the difference? Derivative is supposed to give you the slope at any point, so what does implicit derivative do?
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wrote...
11 years ago
Using the "jazzy stuff" you have dy/dx = -x(r^2 - x^2)^(- 1/2)

which is correct but (r^2 - x^2)^(- 1/2) = y

So they are both the same.
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