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leobiologo leobiologo
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11 years ago
A piece of steel is held firmly in the jaws of a vise. A force larger than 3350N will cause the piece of steel to start to move out of the vise. If the coefficient of friction between the steel and each of the jaws of the vise is 0.825 and each jaw applies an equal force, what is the magnitude of the normal force exerted on the steel by each jaw?

So I know Fsmax = Fn * the coeffeienct but Im not sure if I use 3350 or a different number?
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11 years ago
Yes, because the force of 3350 N is just enough to cause the steel to slip, you are looking for the maximum static friction force.  

Remember, though, that this applied force of 3350 N is being opposed by TWO static frictional forces, one on each side of the steel.
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