× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
d
4
N
3
3
R
3
k
3
o
3
Z
3
j
3
s
3
d
3
J
3
1
3
Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
New Topic  
Smoores Smoores
wrote...
Posts: 100
Rep: 0 0
11 years ago
How much Ca(OH)2 is required to remove 90% of the PO4 3- from 5.5 * 10^8 L of drinking water containing 25 mg/L of PO4 3-?
Read 1073 times
1 Reply

Related Topics

Replies
wrote...
#1
11 years ago
Ca(OH)2 + 2PO4^3- Rightwards Arrow Ca3(PO4)2 +2OH

5.5x10^8 L (25mg/L) = 137.5 mg PO4 = .1375 g PO4 = .00145 mol PO4
.00145/2 = 7.24x10^-4 mol Ca(OH)2
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  1408 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 382
  
 942
  
 401
Your Opinion
Which industry do you think artificial intelligence (AI) will impact the most?
Votes: 484
Previous poll results: Where do you get your textbooks?