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tethead tethead
wrote...
Posts: 1298
Rep: 6 0
6 years ago
Using a normal curve table, the Z score a person would need to be in the top 5% of a class is
A) -5%, which corresponds to a Z score of -.12.
B) 5%, which corresponds to a Z score of .12.
C) 5% - 50% = -45%, which corresponds to a Z score of -1.64.
D) 50% - 5% = 45%, which corresponds to a Z score of 1.64.
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aeLiaLaeLiaL
wrote...
Top Poster
Posts: 828
6 years ago
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tethead Author
wrote...
6 years ago
That's exactly what I needed
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