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4bio 4bio
wrote...
Posts: 47
Rep: 3 0
6 years ago
Lemna minor, a species of duckweed, can reproduce to form new plants very quickly. Suppose that a small backyard pond of 100 L contains 25 Lemna minor plants, and the expected growth rate of the population is 1.0 x 10^2 plants per day.

Numerical Response:
 
The density of the Duckweed population on the 150th day is _______ /mL.
 
Record the answer to three significant digits.
 
_____/ mL
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Replies
wrote...
Educator
6 years ago
In the pond, there exists AT PRESENT: 25 per 100 L or 0.25 lemna / L

We're assuming linear growth, therefore use y = mx + b, where m is the rate provided at 100 plants / day.

y = 100 (x) + b

x represents the number of days, while b represents the current number of Lemna, which is 25.

y = 100 (x) + 25, so set x to 150

y = 100 (150) + 25

y = 15025 on the 150th day.

Change L to mL Rightwards Arrow 100 L Rightwards Arrow 100, 000 mL

Population Density = Number of People / Land Area.

15025 / 100, 000 =

0.15025 Lemna / mL

Hope this makes sense.
4bio Author
wrote...
6 years ago
Yes, thank you!
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