× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
r
4
Home Q & A Board Science-Related Homework Help Mathematics
New Topic  
blahhumbug blahhumbug
wrote...
Posts: 8
Rep: 0 0
6 years ago
Twelve dieters lost an average of 9.8 pounds in 6 weeks when given a special diet plus a "fat-blocking" herbal formula. A control group of twelve other dieters were given the same diet, but without the herbal formula, and lost an average of 8.8 pounds during the same time. The standard deviation of the "fat-blocker" sample was 2.6 and the standard deviation of the control group was 2.8. Find the 95% confidence interval for the differences of the means.
Read 1254 times
1 Reply

Related Topics

Replies
Answer rejected by topic starter
wrote...
#1
Educator
6 years ago
Mean 1: 9.8
Mean 2: 8.8
N1: 12
N2: 12
Std Dev.1: 2.6
Std Dev.2: 2.8

z for 95% CI= 1.96

Difference between means:
M1-M2=9.8-8.8=1
sd=5.1596; se=1.103

Margin of error = \pm 1.96(0.1103)
95% CI of difference:
-1.0319 <1< 3.0319

Right option is

B)

-1.0<mu1-mu2<3.0
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  1187 People Browsing
 124 Signed Up Today
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Related Images
  
 365
  
 295
  
 331
Your Opinion
What percentage of nature vs. nurture dictates human intelligence?
Votes: 431
Previous poll results: Do you believe in global warming?