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6 years ago
Twelve dieters lost an average of 9.8 pounds in 6 weeks when given a special diet plus a "fat-blocking" herbal formula. A control group of twelve other dieters were given the same diet, but without the herbal formula, and lost an average of 8.8 pounds during the same time. The standard deviation of the "fat-blocker" sample was 2.6 and the standard deviation of the control group was 2.8. Find the 95% confidence interval for the differences of the means.
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Educator
6 years ago
Mean 1: 9.8
Mean 2: 8.8
N1: 12
N2: 12
Std Dev.1: 2.6
Std Dev.2: 2.8

z for 95% CI= 1.96

Difference between means:
M1-M2=9.8-8.8=1
sd=5.1596; se=1.103

Margin of error = \pm 1.96(0.1103)
95% CI of difference:
-1.0319 <1< 3.0319

Right option is

B)

-1.0<mu1-mu2<3.0
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