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Home Q & A Board Science-Related Homework Help Physics
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__Aycee __Aycee
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11 years ago
Find the energy (in eV) of an optical photon of frequency 6.43x10^14 Hz

a. 3.27eV
b. 1.62eV
c. 1.94eV
d. 2.66eV
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wrote...
#1
11 years ago
Energy of photon
=hf (in joules)
=hf/e (in eV) (where, e=1.6x10^-19)
=6.63x10^-34x6.43x10^14/(1.6x10^-19)
=2.66 eV

Answer is d. 2.66eV
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