× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
n
3
j
3
x
2
c
2
2
p
2
n
2
3
2
C
2
z
2
k
2
d
2
Home Q & A Board Science-Related Homework Help Physics
New Topic  
field93 field93
wrote...
Posts: 13
Rep: 0 0
11 years ago
I'm not sure if I worded the question above right, but E6-E5 is the energy difference (is it going from E6 to E5 or vice versa?). Also, how would I determine the wavelength of the photon of the frequency calculated? Does it relate to V = (lambda)(frequency)? Is V equal to 3.0 X 10^8 m/s; the speed of light? Thanks.
Read 350 times
1 Reply

Related Topics

Replies
wrote...
#1
11 years ago
The energy difference E6 - E5

is -13.6eV/36 - (-13.6/25) = 0.166222eV * 1.60x10^-19J/eV = 2.65956x10^-20J

Now we have E = h*f         where h = Planck's constant =>

f = E/h = 2.65956x10^-20/6.63x10^-34 = 4.01x10^13Hz

So ? = c/f = 3.0x10^8/4.01x10^13 = 7.48x10^-6m
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  943 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 625
  
 163
  
 872
Your Opinion
Who's your favorite biologist?
Votes: 586
Previous poll results: Who will win the 2024 president election?