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Home Q & A Board Science-Related Homework Help Physics
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field93 field93
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11 years ago
I'm not sure if I worded the question above right, but E6-E5 is the energy difference (is it going from E6 to E5 or vice versa?). Also, how would I determine the wavelength of the photon of the frequency calculated? Does it relate to V = (lambda)(frequency)? Is V equal to 3.0 X 10^8 m/s; the speed of light? Thanks.
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11 years ago
The energy difference E6 - E5

is -13.6eV/36 - (-13.6/25) = 0.166222eV * 1.60x10^-19J/eV = 2.65956x10^-20J

Now we have E = h*f         where h = Planck's constant =>

f = E/h = 2.65956x10^-20/6.63x10^-34 = 4.01x10^13Hz

So ? = c/f = 3.0x10^8/4.01x10^13 = 7.48x10^-6m
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