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rishi95 rishi95
wrote...
11 years ago
Use the henderson hasselbalch equation to calculate the pH of each solution:
 a.) a solution that contains 0.685% C5H5N by mass and 0.980% C5H5NHCl by mass.
B.) A soluton that is 17.0 g of HF and 25.0 g of NaF in 125 mL of solution
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wrote...
11 years ago
(b).

pH = pKa + log ([base conjugate]/[acid])

pH = 3.2 + log ([(25/(23 + 19))]/[(17/(1 + 19))])

pH = 3.045
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