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smith123 smith123
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Posts: 49
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11 years ago
Acid 1 has a pKa of 4.3 and Acid 2 has a pKa of 5.2.
Both Acid 1 and Acid 2 were titrated using the strong base NaOH. A volume of 25 mL of each acid was titrated to the equivalence point with 20.00 mL of .100 M NaOH. What is true about the concentrations of the acids?
Best answer will get rewarded points.
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wrote...
11 years ago
Find Ka, which is (molarity of acid ions)x(molarity of conjugate base ions) all divided by the remnant undissolved acid.  to find pKa, its -log(Ka).  the logarithm is base 10, not the natural log ln.

not doing the work for you, so cheers Slight Smile
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