oxidation/reduction

chels194

wrote...

13 years ago

1) Use the following data?
1. Cu3+ + 2e- -> Cu+ E1=1.28 V
2. Cu2+ + e- -> Cu+ E2= 0.15V
3. Cu2+ + 2e- -> Cu E3= 0.34 V
4. Cu+ + e- -> Cu E4= 0.52 V

Calculate the standard reduction potential for the reaction of Cu (III) to Cu (II)

2) Rank these species by their ability to act as an oxidizing agent?
In order with best oxidizing agent in the beginning to best reducing agent, the end

So this is what I got:
F2, I2, Ca2+, Cr 3+.........................is it right ?

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bio_man

wrote...

Educator

13 years ago Edited: 13 years ago, bio_man

This looks like chemistry Sad Dummy

Half-reactions...

Eºcell = Eºreduction (Cathode) - Eºreduction (Anode)

For number two, I know Ca2+, Cr 3+ is correct but I'm not too sure about the elements F and I. Metals atoms are reducing agents as they lose electrons to form positive ions. The order in which they do this is their reactivity. The process you are seeking is the reverse and the metals will be in the reverse order of their reactivities.

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chels194 Author

wrote...

13 years ago

I still don't get the first part. So would it be 1.28 and .34? can u show me this.

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chels194 Author

wrote...

13 years ago

never mind. i got it Smiling Face with Open Mouth

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bio_man

wrote...

Educator

13 years ago

How did you solve it, I'm curious... Can you provide me with the solutions this time Neutral Face

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chels194 Author

wrote...

13 years ago

Cu3+ + 2e- -> Cu+ delta G1= -2 FE1
Cu+ -> Cu2+ + e- delta G2= -1F(-E2)
--------------------------
Cu 3+ + e- -> Cu2+ delta G tot = FE2-2FE1= F(E2-2E1)

delta G= -nFE or E= - delta GlnF

Etot= - (.15V -2 (1.28V)) / (1) = 2.41 V

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bio_man

wrote...

Educator

13 years ago

Much thanks.

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