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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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nevada nevada
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10 years ago
The freezing point of t-butanol is 25.5C and Kf is 9.lC.kg/mol. Usually t-butanol absorbs water on exposure to air. If the freezing point of a 10g sample of t-butanol is 24.5C. How many grams.of water are present in the sample?

i am trying to understand the steps to this question but the way my teacher did it, is confusing me.

∆T=Kf*m
∆T=25.5-24.59=0.91
0.91=9.1(m)
m=0.1mol H2O
mol H2O=massH2O/ MWH2O= x/ 18g
kg solvent= (10-x) * 1kg/1000g


0.1=x/18 / (10-x)/1000 =1000X / 180-18x
18-1.8X=1000X

x=0.018g H2O

can you please explain how to do this?


thank you!
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padrepadre
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10 years ago
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