Using the heat of combustion of methanol as -726.6 kJ/mol and the following data:
C(graphite) + 1/2 O2→CO(g) ΔH° = -110.5 kJ/mol
C(graphite) + O2(g) → CO2(g) ΔH° = -393.5 kJ/mol
H2(g) + 1/2 O2(g) → H2O(l) ΔH° = -285.8 kJ/mol
Determine ΔrH° for the following reaction:
CO(g) + 2 H2(g) → CH3OH(l)
▸ -349 kJ/mol
▸ 157.8 kJ/mol
▸ -157.8 kJ/mol
▸ 128 kJ/mol
▸ -128 kJ/mol