PPK please help me with this question..

What have you done so far?

Sir. i just solved this yet...

B = brown. b = cream. H = straight. h = curly.
Parent 1 - heterozygous brown, curly-haired (Bbhh genotype).
Parent 2 - cream, homozygous straight-haired (bbHH genotype).

Gamets: Bh, bh (1st parent)
      bH (2nd parent)


and i dont know how to solve punnete square, phenotype and genotype of offspring.. PLEASE HELP me my exam is on monday..

I can help, make a punnet square like this (4 X 4):

	Bh	Bh	bh	bh
bH
bH
bH
bH

And fill it out

@star.. you are genius... peoples were giving me different answer and i was confused and that's why i was keep asking the same question on this forum. Thanks alot. By the way my original tutor from school game me the exact answer you mentioned on quote.

I wrote on your other thread:

2. B = brown. b = cream. H = straight. h = curly.

Parent 1 - heterozygous brown, curly-haired (Bbhh genotype).
Parent 2 - cream, homozygous straight-haired (bbHH genotype).

    B  b                  h  h
b  Bb bb           H  Hh Hh
b  Bb bb           H  Hh Hh

1/2 (2/4) Bb      1 (4/4) Hh
1/2 (2/4) bb

Genotypes of offspring:
50% of F1 will have BbHh genotype.
50% of F1 will have bbHh genotype.

Phenotypes of offspring:
50% of F1 will have brown, straight hair (from BbHh genotype).
50% of F1 will have cream, straight hair (from bbHh genotype).

Bulgaria.. Thanks alot dear.
Actually your is a bit different. You got 2 punette square and i got 1.

What i did in my punette sqaure.

   Bh            bH
bH   BbHh    bbHh
Bh   Bbhh            bbhh

The F1 generation will then be

25% BbHh (heterozygous for both brown coat and straight hair)
25% bbHh (cream-colored coat and heterozygous for straight hair)
25% Bbhh (heterozygous brown coat and curly hair)
25% bbhh (homozygous cream-colored coat and curly hair)


Would you check my work please. If i'm incorrect. correct me please. Thanks