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Maria Maria
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Posts: 488
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6 years ago
In Drosophila, a narrow, reduced eye is called a bar-eye. It is due to a dominant X-linked allele (B),
  while the full wild-type is due to the recessive gene (B+). Give the F1 and F2 genotypic and
  phenotypic expectations of a cross of a homozygous wild-type female with a bar-eyed male. What will be an ideal response?
 
 

Question 2

In humans, an X-linked disorder called coloboma iridia (a fissure in the iris) is a recessive trait. A
  normal couple has an afflicted daughter. The husband sues the wife for divorce on the grounds of
  infidelity. Would you vote in his favor? What will be an ideal response?
 
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Replies
wrote...
6 years ago
Answer to q. 1

B+B+  BY  F1: B+B wild female, B+Y wild male; F2: 1/4 BY bar male, 1/4 B+Y wild male, 1/4
B+B+ wild female, 1/4 B+B wild female

Answer to q. 2

Yes, the daughter would have to inherit the recessive trait from both parents.
Maria Author
wrote...
6 years ago
Passed my quiz with this!
wrote...
6 years ago
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