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toodaloo toodaloo
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10 years ago
msg me
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Doctor-2-BDoctor-2-B
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#1
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toodaloo Author
wrote...
#2
10 years ago
dw im done #8
Post Merge: 10 years ago

and 7
wrote...
#3
Donated
Valued Member
10 years ago
#5:
380, 120, 120, 380

6. If the percent G + C content of a DNA molecule is 34%, then what are the percentages
of the four individual bases (A,T,G and C) (1 mark)?
%A=33 %T=33 %G=17 %C=17
Post Merge: 10 years ago

#4:
1,2,4,5
Pretty fly for a SciGuy
toodaloo Author
wrote...
#4
10 years ago
and 4
wrote...
#5
Donated
Valued Member
10 years ago
#3:
PQMON
3,1,2,4
(they all require P, 3 requires Q, 1 requires M, 2 requires O, and 4 requires N)
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toodaloo Author
wrote...
#6
10 years ago
are you sure about 3 i got nomqp
wrote...
#7
Staff Member
Educator
10 years ago
Quote from: toodaloo (10 years ago)
are you sure about 3 i got nomqp

now you owe him a donation Slight Smile
Mastering in Nutritional Biology
Tralalalala Slight Smile
toodaloo Author
wrote...
#8
10 years ago
lol definitely
wrote...
#9
Donated
Valued Member
10 years ago Edited: 10 years ago, Doctor-2-B
1a.
Cb

Ge---------Cb---------St
      7.1          7.1

Interference = 1 - Observed DR/Expected DR
1 - 6/5.041 = -0.19024
Post Merge: 10 years ago

Not sure.  Go with what you think  It's one or the other.  Just can't think of if it's forward or backward.

For #2a:
+++ is missing because those are the females who are unaffected
2b:
bac

That's all I got.  Good luck.
Post Merge: 10 years ago

Just checked it.  It's NOMQP
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toodaloo Author
wrote...
#10
10 years ago Edited: 10 years ago, toodaloo
can you check #1 again based on this attachement
it's a very similar question except some +'s and - are in different places
Post Merge: 10 years ago

oh and the numbers are different clearly
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wrote...
#11
10 years ago
nvm figured it out  Smiling Face with Open Mouth
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#12
Donated
Valued Member
10 years ago
a.
Cb

b.
Ge-Cb
(46+43+6)/1000 = 0.095 * 100 = 9.5 mu

Cb-St
(22+19+6)/1000 = 0.047 * 100 = 4.7 mu

Ge----------------------Cb-----------St
           9.5 mu          4.7 mu

c.
Observed double recombinants: 6
Expected double recombinants: (0.095)(0.047) = 0.004465*1000 = 4.465
Interference = 1 - 6/4.465 = -0.34378
Pretty fly for a SciGuy
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