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kz1234 kz1234
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10 years ago
What are the equilibrium partial pressures of CO and CO2 if CO is the only gas present initially, at a partial pressure of 0.950atm ?
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10 years ago
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What are the equilibrium partial pressures of CO and CO2 if CO is the only gas present initially, at a partial pressure of 0.938 atm? At 1000 K, Kp= 19.9 for the reaction Fe2O3 + 3CO Rightwards Arrow 2Fe + 3 CO2

Answer:

total pressure = partial prssure x mole fraction
initially only CO present , hence mole fraction =1
hence total pressure = 0.938 atm
at equilibrium CO moles =3-3x , CO2 moles = 3x , total moles = 3
Kp=19.9 = (3x/3) x0.938^3 / (3-3x/3) x 0.938^3 = 3x/(3-3x)
x=0.952moles
equilibrium partial pressure of CO = (3-3x0.952) x 0.938 = 0.1347 atm
equilibrium partial pressure of CO2 = 3 x 0.952 x 0.938 = 2.678 atm

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