*URGENT* Population genetics

Assuming these are hardy weingburg problems:
1. It would be 32% because 20/500=0.04 which is the frequency of phenotype of recessive. You square root this number to get .2 or 20% for the allele of the recessive gene. This means that 80% of the allele frequency is dominant. Remember the equation to get heterozygous genotype is 2*p*q so (p being dominant and aqbeing recessive) so 2*.2*.8=.32 or 32%.

2. It is a. You are correct, square root of 1/2500=.02 which is a. Remember the formula. p is dominant allele. q is recessive allele frequency. p^2 is dominant genotype frequency. q^2 is recessive genotype frequency. 2*p*q= heterozygous genotype frequency. When solving a problem, always try to solve the recessive frequency because remember in genotype, dominant and heterozygous display the same traits so you can't tell which is which. Hope this helps!

Post Merge: 10 years ago

oops my bad, i meant to say phenotype for p^2, q^2, and 2pq and that in phenotype, dominant and heterozygous display same traits.