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Dragon.amg86 Dragon.amg86
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Posts: 655
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6 years ago
Suppose that 1 customer arrives each minute in a Poisson distribution. Is it more likely that 2 customers or 0 customers will arrive each minute?
 
  What will be an ideal response?
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wrote...
6 years ago
P(0 ) = e(-1 )(10 )/0 = .368
P(2 ) = e(-1 )(12 )/2 = .184
Thus it is more likely that 0 customers will arrive each minute.
Dragon.amg86 Author
wrote...
6 years ago
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