For the following z-test statistic, compute the p-value assuming that the hypothesis test is a one-tailed test: z = 2.09.
A) 0.0172
B) 0.0183
C) 0.0415
D) 0.0611
Q. 2If the standard deviation for a Poisson distribution is known to be 3, the expected value of that Poison distribution is:
A) 3
B) about 1.73
C) 9
D) Can't be determined without more information.
Q. 3For the following z-test statistic, compute the p-value assuming that the hypothesis test is a one-tailed test: z = 1.34.
A) 0.0606
B) 0.0815
C) 0.0124
D) 0.0901
Q. 4The manager of a movie theater has determined that the distribution of customers arriving at the concession stand is Poisson distributed with a standard deviation equal to 2 people per 10 minutes.
What is the probability that 0 customers arrive during a 10-minute period?A) 0.1353
B) 0.0183
C) 0.9817
D) Essentially 0
Q. 5The Lottaburger restaurant chain in central New Mexico is conducting an analysis of its restaurants, which take pride in serving burgers and fries to go faster than the competition.
As a part of its analysis, Lottaburger wants to determine if its speed of service is different across its four outlets. Orders at Lottaburger restaurants are tracked electronically, and the chain is able to determine the speed with which every order is filled. The chain decided to randomly sample 20 orders from each of the four restaurants it operates. The speed of service for each randomly sampled order was noted and is contained in the file Lottaburger.At the alpha = 0.05 level of service, can Lottaburger conclude that the speed of service is different across the four restaurants in the chain?A) Since F = 18.418 > F=0.05 = 2.725, reject the null hypothesis. Based on these sample data we can conclude that the average service time is different across the four restaurants in the chain.
B) Since F = 22.666 > F=0.05 = 2.725, reject the null hypothesis. Based on these sample data we can conclude that the average service time is different across the four restaurants in the chain.
C) Since F = 22.666 > F=0.05 = 2.725, do not reject the null hypothesis. Based on these sample data there is not sufficient evidence to conclude that the average service time is different across the four restaurants in the chain.
D) Since F = 18.418 > F=0.05 = 2.725, do not reject the null hypothesis. Based on these sample data there is not sufficient evidence to conclude that the average service time is different across the four restaurants in the chain.