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Home Q & A Board Biology-Related Homework Help General Biology
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ladye ladye
wrote...
13 years ago
Please show me the steps with a quick explanation

Two equally charged balls, each of mass 0.10gm, are suspended from the same point by 13 cm long.The balls come to rest 10cm due to electrostatic replusion. Determine the charge on each ball.

Determine the acceleration of a proton in an electric field of 500 N/C. How many times is this greater than that due to gravity? The proton mass is 1.6 x 10^-27 kg?
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#1
Donated
Trusted Member
13 years ago
Wrong forum Face with Rolling Eyes

Rightwards Arrow We know that...

F = k*(q1q2)/(r2)

...and also

F = G*(m1m2)/(r2)

so we can say that:

k*(q1q2)/(r2) = G*(m1m2)/(r2)

q1*q2 = G*(m1m2)/(k)

by putting values we get the product q1*q2

take the under root of the answer and you will get the values of q1 and q2 separately...

I found this on some forum


Electric field of intensity E = 500 N/C

SO, accleration of the proton  a = E q / m

... where  q = charge = 1.6 * 10 ^ 1-9 C
            m = mass = 1.67 * 10-27 kg

substitue values we get  a  = 4.79 ×1010 m/s2 in the direction of the electric field.
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