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Home Q & A Board Science-Related Homework Help Physics
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o.avworo o.avworo
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11 years ago
A 0.075 kg ball in a kinetic sculpture moves at a constant soeed along a motorized conveyor belt. The ball rises 1.32 m above the ground. A constant frictional force of 0.350 N acts in the direction opposite the conveyor belt's motion. What is the net work done on the ball?
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wrote...
#1
11 years ago
good luck
wrote...
#2
11 years ago
By definition W = Fd.  Since the ball is moving from one height to another, we are increasing the potential energy of the ball, which is equal to the work done on the ball.  Therefore W = mgd
= (0.075 kg)(9.81 m/s/s)(1.32 m) = 0.97 J.  This is similar to walking up a flight of stairs.  No work is done moving horizontally, only when moving from one floor to another.
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