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Jess8219 Jess8219
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3 years ago
what is the empirical formula of a compound that is 15.9% boron and 84.1% fluorine?
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Educator
3 years ago
15.9% boron > 0.159 and 84.1% fluorine > 0.841

molar mass of B : 10.81

15.9 / 10.81 = 1.4708
84.1 / 18.99 = 4.4286

1.4708 : 4.4286

Divide by lowest term:

1 : 2.91

Or 1:~3

BF3
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