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patrick19 patrick19
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3 years ago
The answer that I got is f(x)= -0.2x(x+6)(x-5), would that be correct?
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#1
Educator
3 years ago
No, it's wrong because your function clearly shows 3 distinct zeros, while the in the graph provided, the function crosses the x-axis only twice.
patrick19 Author
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#2
3 years ago
This is what I did to get the answer. How would I fix this?
x = -6 x= 5
f(x) = a(x+6)(x-5)
f(0)= 0 = a (0+6)(0-5)
= -30
f(-5) = -10 = a (-5 + 6) (-5-5)
-10/50 = a (50)/50
-0.2 = a
Therefore, f(x)= -0.2x (x+6)(x-5)
wrote...
#3
Educator
3 years ago
See my solution:
wrote...
#4
Educator
3 years ago
Actually I think I'm wrong Frowning Face Were you told if it's a cubic or quartic?
patrick19 Author
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#5
3 years ago Edited: 3 years ago, patrick19
Doesn't tell me, but I believe it's quartic
Post Merge: 3 years ago

can I just replace the 2 with a 3?
wrote...
#6
Educator
3 years ago
Yeah, I think it's 1/28 instead of negative, and raised to a power of 3 instead of 2
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