If you are looking at a graph of a quadratic equation, how do you determine where the solutions are?

The solutions are where the graph crosses the x axis. Could be 0, 1, or 2 solutions.

The solutions are wherever the graph crosses the x axis.

The (real) solutions are whenever the graph crosses the x-axis at y=0

As many as two, as few as zero

solutions are the value of x on the x axis y=0.

depends.if the eq is:y^2+y+2=0,then u have 2 look at the points where the curve intersects with the Y axis and not the X axis.similarly x^2+x+2=0,means that you have to look at the points where the curve intersects with the X axis and not the Y axis.

where the graph crosses the x-axis.

you can find out mathematically by factoring

X^2 +2X + 1
(X +1) (X+1)
the graph would cross at (0, -1)

the solutions are the intersection points of the curve with the x -axis

depends.if the eq is:y^2+2y+5=0,then u have to look at the Y axis and not the X axis.similarly x^2+3x+8=0,means that you have to look at the curve intersects with the X axis and not the Y axis. This is the solution. Do u satisfied.

You have three potential cases:
1) the graph cuts the x-axis at two distinct points.
2) the graph has a single point where it touches the x-axis
3) the graph never touches the x-axis

In case (1), the equation has two distinct, real roots. In case (2), the equation has a repeated, real root. In case (3), the equation has a pair of complex roots, one of which is the complex conjugate of the other.

The criterion that establishes which of these situations obtains is called the discriminant, and it is the term inside the square root of the quadratic formula for a x² + b x + c = 0: b² - 4 a c
If the discriminant is positive, the equation has two real, distinct roots. If the discriminant is zero, the equation has two repeated roots. If it is negative, the equation has two complex conjugate roots.