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adegob adegob
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2 years ago
Combustion of 493 mg of a hydrocarbon gave 1549 mg CO2 and 633.9 mg H2O. What is the molecular formula if the molecular weight is subsequently found to be 42?

▸ CO2

▸ CH2

▸ C6H12

▸ C2H2O

▸ C3H6
Textbook 
General Chemistry: Principles and Modern Applications

General Chemistry: Principles and Modern Applications


Edition: 11th
Authors:
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balibali
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2 years ago
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