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wrote...
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3 months ago
So there's a DNA sequence with a double stranded
DNA with a open reading frame encoding a small
polypeptide 5'
ATGGAGGAACCGCAGTCAGATCCTAGCTA GGTC3'
3' TACCTCCTTGGCGTCAGTCTAGGATCGAT CCAG 5'
So the mRNA transcribed from this DNA template
would be Since RNA uses uracil instead of thymine,
replaced all instances of "T" in the DNA sequence
with "U". This resulted in the mRNA sequence: 5'
UACCUCCUUGGCGUUCAGUCUAGGATCGA TCCAG
3'. ?? I'm I right or have I got this wrong ?? Would
this indicate the 5 print and. 3 prime ends of the
mRNA??

Or would it be
Or would it be 5' AUGGAGGAACCCGACGUCAGACCUACGAG GUC 3' ?
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wrote...
Educator
3 months ago Edited: 3 months ago, bio_man
It really depends on which strand is chosen as the coding strand (the non-template strand). Ultimately, the choice of which strand RNA chooses as the template strand depends on the orientation of the gene. For simplicity, however, if this happens to be the coding strand (non-template strand):

5'-ATG GAG GAA CCG CAG TCA GAT CCT AGC TAG GTC-3'

Then the other strand (below) is used to generate the mRNA.

3'-TAC CTC CTT GGC GTC AGT CTA GGA TCG ATC CAG-5'

This gets translated to:

5'-AUG GAG GAA CCG CAG UCA GAU CCU AGC UAG GUC-3'

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