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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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bugaian bugaian
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Posts: 123
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12 years ago
Write the chemical equation.
At a temperature of 400 degrees C and a total pressure of 250 atm, 0.720g of NH3 was produced by the reaction 2.80g N2, with excess H2.
What is the percent yield of this reaction?
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#1
12 years ago
N2  +  3 H2  Rightwards Arrow  2 NH3
moles of N2  =  2.80 / 28  =  0.100  (Mr of N2 = 28)
expected moles of NH3  =  0.200  (1:2 ratio in equation)
expected mass of NH3  =  0.200 * 17  =  3.40g  (Mr of NH3 = 17)
%yield  =  (0.720/3.40)*100  =  21.2%
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