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lgood4 lgood4
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13 years ago
An elevator has a mass of 900 kg and carries a maximum load of 688 kg. A constant
frictional force of 4890 N retards its motion upward.


What power must the motor deliver at an
instantaneous speed of 4.21 m/s if the elevator
is designed to provide an upward acceleration
of 1.02 m/s?
Answer in units of W

Thanks!
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wrote...
#1
13 years ago
p=mad/t
vf^2=vi^2+2ax
vf=vi+at

(((900+688)*(1.02+9.8)-4890)*8.68)/4.13
use your calculator
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