× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
r
4
Home Q & A Board Science-Related Homework Help Physics
New Topic  
julie7 julie7
wrote...
Posts: 111
Rep: 0 0
11 years ago
I push sideways on a box that masses 10kg that has a µ of 0.21 with the surface it sits on. It just begins to move, but I keep pushing with the same force. 5 seconds later it is 1.88m away. What is µk?
Read 470 times
1 Reply

Related Topics

Replies
wrote...
#1
11 years ago
static friction Fs = µFn = 0.21 * 10kg * 9.8m/s² = 20.58 N
This, then, is the applied force.

In order to have travelled 1.88m in 5 s from rest with uniform acceleration,
s = 1.88m = ½at² = ½ * a * (5s)²
a = 0.15 m/s²
This implies that the net force Fnet = ma = 10kg * 0.15m/s² = 1.5 N
Then the kinetic friction Fk = Fapp - Fnet = 20.58N - 1.5N = 19.08 N

kinetic µ = Fk / mg = 19.08N / 98N = 0.19 m/s²
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  1289 People Browsing
 114 Signed Up Today
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Related Images
  
 98
  
 370
  
 168
Your Opinion
Previous poll results: Who will win the 2024 president election?