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darwinshuffle darwinshuffle
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11 years ago
The plates of a parallel-plate capacitor are maintained with constant voltage by a battery as they are pulled apart. During this process, the amount of charge on the plates must:

A) increase
B) decrease
C) remain constant
D) either increase or decrease. There is no way to tell from the information given

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#1
11 years ago
The capacitance decreases as the plates are pulled apart. (In fact C is inversely proportional to plate separation,d - see link.)

C = Q/V so V = Q/C

Since V is held constant and C decreases, Q must also decrease (so Q/C remains the same value). Answer B.
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