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Mike146 Mike146
wrote...
Posts: 33
Rep: 0 0
12 years ago
A single gene with two alleles exists in Hardy-Weinberg equilibrium within a population. If the frequency of each allele is 0.5, what would be the expected frequency of the heterozygous genotype.

a)0.25
b)0.75
c)0.33
d)0.20
e)0.50
I think I know the answer actually:

Homozygous dominant:
0.5 x 0.5 = 0.25 (p x p = p2)

Homozygous recessive:
0.5 x 0.5 = 0.25 (q x q = q2)

Therefore the heterozygous frequency must be 0.50 (e.)

Is this right, if not please could someone help? Thanks
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Answer accepted by topic starter
smile92smile92
wrote...
Posts: 40
Rep: 5 0
12 years ago
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