Calculate the molarity of 100 ug/ml solutions of glucose, fructose and xylose?

what you should know:  basic stoichiometry, molar mass glucose =180 g, molar mass fructose =180 g, molar mass xylose =150 g; Molarity =mol/L, 1 x10^6 ug =1 g, 1 x10^3 mL =1 L, 1 mol =amount of a substance

1. solve for L using the molarity equation
100 ug/mL x(1000 mL/1 L)= ANS

2. solve for mol using the molarity equation
100 ug/mL x(1 g/1 x10^6 ug) x(1 mol/180 g)= ANS

3. solve for M using the molarity equation
M=mol/L =ANS 2/ANS 1

repeat steps for fructose and xylose. note that fructose and glucose has same molar mass so ANS is the same for both.  use a calculator to compute the expression.