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tole034 tole034
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11 years ago
The vapor pressure of water at 20 degrees celsius is 17.5 torr. A 20% solution of the nonvolatile solute C2H4(OH)2 (molecular mass 62.0 g/mol), in water is prepared. Estimate the vapor pressure of the solution.

I know that you are supposed to use raoult's law here but could somebody please explain the proper steps and reasonings within the problem and raoult's law in order to derive the answer? Thanks
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#1
11 years ago
mass C2H4(OH)2 = 20 g
moles C2H4(OH)2 = 20 / 62.0=0.323
mass water = 80 g
moles water = 80 / 18 g/mol=4.44
mole fraction water = 4.44 / 4.44 + 0.323 =0.932
p = 0.932 x 17.5 =16.3 torr
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