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Jedi_Knight Jedi_Knight
wrote...
Posts: 12
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8 years ago
Using Pearson biologylabsonline website. Performed cross of wild female X brown eye, dumpy wing male and backcrossed F1 wild female offspring with P1 male.
These were the results:

  Results of Cross #2 BACKCROSS                         

                                Parents     (F1 femals & P1 male)                           

                      (Female: +) x (Male: BW;DP)                       

                               Offspring    (backcross offspring)                           

            Phenotype                   Number   Proportion    Ratio   
Female: +                                 1419     0.1429      1.391   
Male: +                                   1461     0.1471      1.432   
Female: BW                                1020     0.1027      1.000   
Male: BW                                  1034     0.1041      1.014   
Female: DP                                1098     0.1105      1.076   
Male: DP                                  1048     0.1055      1.027   
Female: BW;DP                             1441     0.1451      1.413   
Male: BW;DP                               1412     0.1422      1.384   
 Total                                   9933

-------------------------------------------------------------------------


                          Results of Cross #2 BACKCROSS                         
                              Ignoring Sex                             

                                Parents      (F1 female and P1 male)                           

                      (Female: +) x (Male: BW;DP)                       

                               Offspring      (Backcross offspring)                         

            Phenotype                   Number   Proportion    Ratio   
+                                         2880     0.2899      1.402   
BW                                        2054     0.2068      1.000   
DP                                        2146     0.2160      1.045   
BW;DP                                     2853     0.2872      1.389   
 Total                                   9933


Here is what I don't understand, and the answer I need: How do these genes show independent assortment and what evidence does these data provide to support the answer to this question?
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wrote...
8 years ago
Numbers should be equally probably is independent assortment is taking place.

Without really looking at the genes in this particular question, let's say you have: Aa, Ab, Ba, Bb

You will need two generations of breeding. (Aa, Ab, Ba, Bb) X (Aa, Ab, Ba, Bb) on the second generation , all 16 will be equally probable at a ratio of 9:3:3:1 phenotype.
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