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buffyoumofo buffyoumofo
wrote...
Posts: 126
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12 years ago
I need to write the balanced net ionic equation for the complete neutralization of H2SO3 with aqueous NaOH the need to know what the total charge on the right side of the bablanced equation is? Can someone help me with this please
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wrote...
12 years ago
so you should get a salt i believe

unbalanced equation
NaOH +H2SO3 Rightwards Arrow Na2SO3 +H2O

balanced
2NaOH +H2SO3 ---> Na2SO3 +2H2O
wrote...
12 years ago
I'm assuming you meant H2SO4, since H2SO3 cannot be isolated in solution.  The equation, in water, is:
2H^+ + SO4^2- + 2Na^+ + 2OH^-  Rightwards Arrow  2H2O + 2Na^+ + SO4^2-
The total charge on both sides is 0; the left side is 2(+1) + (-2) + 2(+1) + 2(-1) = 0 and the right side is 0 + 2(+1) + (-2) = 0

Eliminating all of the ions present on both sides gives us the net ionic equation:
2H^+ + 2OH^-  Rightwards Arrow  2H2O
charges are 2(+1) + 2(-1) = 0 for left side, 0 for right side.

Hope that helps.
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