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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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ilkat ilkat
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11 years ago
A sealed flask contains 0.45g  of water at 28 degrees C . The vapor pressure of water at this temperature is 28.36 mmHg. What is the minimum volume of the flask in order that no liquid water be present in the flask?
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#1
11 years ago
You can just use the ideal gas law to calculate the volume required to contain that amount of water at that temperature and pressure:

moles H2O = 0.45 g / 18.0 g/mol = 0.025 mol
P = 28.36 mmHg / 760 mmHg/atm = 0.0373 atm
T = 28 + 273 = 301 K
R = 0.0821 Latm/molK

Plug those into the ideal gas law:
PV = nRT

and solve for V. Your volume will have units of Liters.
0.0373 atm V = 0.025 mol (0.0821 Latm/molK) 301K
V = 16.6 L
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