It takes 11.53 grams of water to dissolve a mixture of 25 grams of KNO3 and 2 g of CuSO4 at 100 ...

kiz2006

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12 years ago

It takes 11.53 grams of water to dissolve a mixture of 25 grams of KNO3 and 2 g of CuSO4 at 100 ...

It takes 11.53 grams of water to dissolve a mixture of 25 grams of KNO3 and 2 g of CuSO4 at 100 degrees C. If 10 milliliters of deoionized water is added and the solution is cooled to 0 degrees C.

a. How much KNO3 remains in the solution?

b. How much KNO3 crystallizes out?

c. How much CuSO4 crystallizes out?

d. What percentage of KNO3 is recovered from the original 25 grams?

ps. the solubility for KNO3 at 0 degrees is 10 g per 100 g of water
the solubility for CuSO4 at 0 degrees is 20 g per 100 g of water

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sperl

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12 years ago

What have you completed so far?

Rememeber, chemistry is metric, and in this system volume is equivalent to weight when dealing with water. Therefore, 11.53 grams of water is also the volume in milliliters.

The final volume is 11.53 + 10 = 21.53 mls. If 10g of KNO3 dissolve in 100 mls of water at 0 C, then 10g/100mls = 0.1 gm/ml. 21.53 mls will dissolve (21.53 mls)*(0.1 gm/ml) = 2.153 gm KNO3. 25 gm - 2.153 gm = 22.847 gm of KNO3 will crystalize out of the solution.

The calculations for the CuSO4 work exactly the same.

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kiz2006 Author

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12 years ago

so then for CuSO4 crystallizes out by 2.0-2.153g and its 0.153? how about the last one what percentage of kno3 is recovered from the original 25 grams? i dont get that one

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