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Home Q & A Board Science-Related Homework Help High School Level Science
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lex6909 lex6909
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11 years ago
If in a population in Hardy-Weinberg equilibrium the frequency of homozygous recessive genotype is 0.58, then the approximate frequency of the dominant allele will be:
0.12, 0.24, 0.44, 0.88, 0.98

Can someone walk me through this please?
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#1
11 years ago
0.24, and it's done this way:  Let's say the recessive genotype is bb.  Its frequency is 0.58.  Therefore, the frequency of b is sqrt(0.58) = 0.7616.  Since the sum of the frequencies must = 1, the frequency of B is 1 - 0.7616 = 0.2384 or approximately 0.24.
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