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Lexie Lexie
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12 years ago
In a population of 100 individuals 40 are homozygous for unattached earlobes (EE), 50 are heterozygous (Ee) and 10 are homozygous for attached earlobes (ee).  What are the allele frequencies?
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wrote...
12 years ago
thats a good one
wrote...
12 years ago
You don't need the Hardy Weinberg equartion to solve this. It is simple calculation of percent.

total # of specific alleles/total number of alleles.

(40x2)+50/200  is E
(10x2)+10/200 is e
wrote...
12 years ago
The frequency of E is the frequency of EE plus half the frequency of Ee, and the frequency of e is the frequency of ee plus half the frequency of Ee.
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