This is the method presented in the text for finding a circle

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This is the method presented in the text for finding a circle

This is the method presented in the text for finding a circle
whose area is equal to a given square: In square ABCD, let
M be the intersection of the diagonals (see Fig. 8.5). Draw
the circle with M as center and MA as radius; let ME be
the radius of the circle perpendicular to the side AD and
cutting AD in G. Let GN = 1GE. Then MN is the radius 3
of the desired circle. Show that if AB = s and MN = r, √
then r = 2+ 2 . Show that this implies a value for π equal s6
to 3.088311755.

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