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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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LeonBan LeonBan
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11 years ago
A 30.0 mL sample of 0.150 M KOH is titrated with 0.125 M HClO4 solution. Calculate the pH after the following volumes of acid have been added.

36 mL (When I set up the equation, I came up with 0.0045 for both H+ and OH-

37 mL

43 mL
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#1
11 years ago
moles KOH = 0.0300 L x 0.150 M= 0.00450

moles HClO4 = 0.035 L x 0.125 = 0.00450
so pH = 7.0

moles HClO4 = 0.037 L x 0.125 M=0.00463
moles HClO4 in excess = 0.00463 - 0.00450=0.000130
total volume = 30 + 37 = 67 mL = 0.067 L
[H+]= 0.000130/ 0.067 =0.00104 M
pH = 2.71

moles HClO4 = 0.043 x 0.125 M=0.00538
moles HClO4 in excess =0.00538 - 0.00450= 0.000880
total volume = 0.073 L
[H+]= 0.000880 / 0.073 =0.0121 M
pH = 1.92
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